Andy, Beth, and Cindy each went for a walk yesterday afternoon. Andy walked 2 and three fourths mi at a constant speed of 2 and one half mi divided by h . Beth walked 1 and one half mi at a constant speed of 1 and one eighth mi divided by h . Cindy walked for 1 h and 24 min at a constant speed of 1 and one fourth mi divided by h . List the three people in order of the times they spent walking from least time to greatest time. Choose the correct answer below. A. Beth, Cindy, Andy B. Cindy, Andy, Beth
Accepted Solution
A:
Answer:The correct order from least time to greatest time is: Andy, Beth, Cindy.Step-by-step explanation:Consider the provided information,Andy walked [tex]2\frac{3}{4}[/tex] mi at a constant speed of [tex]2 \frac{1}{2}[/tex] mi/h.As we know: [tex]Time= \frac{Distance}{Speed}[/tex][tex]Time= \frac{2\frac{3}{4}}{2 \frac{1}{2}}[/tex][tex]Time= \frac{\frac{11}{4}}{\frac{5}{2}}[/tex][tex]Time= \frac{11}{10}[/tex]Therefore, Andy takes 1.1 hours.Beth walked [tex]1\frac{1}{2}[/tex] mi at a constant speed of [tex]1\frac{1}{8}[/tex] mi/h . [tex]Time= \frac{1\frac{1}{2}}{1 \frac{1}{8}}[/tex][tex]Time= \frac{\frac{3}{2}}{\frac{9}{8}}[/tex][tex]Time= \frac{4}{3}[/tex]Therefore, Beth takes 1.33 hours.Cindy walked for 1 h and 24 min at a constant speed of [tex]1\frac{1}{4}[/tex] mi/h.[tex]1\: hour \: 24 \: minutes \: = 1+ \frac{24}{60}hours = 1.4\ hours[/tex]Therefore Cindy takes 1.4 hours.Andy spent least time i.e 1.1 hours and Cindy spent greatest time i.e 1.4 hours.The correct order from least time to greatest time is: Andy, Beth, Cindy